Find the area of triangle whose vertices are (1,3), (-3,-5). 12,-1)
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Step-by-step explanation:
area of triangle= (1/2) [x1 (y2 – y3 ) + x2 (y3 – y1 ) + x3(y1 – y2)]
A = (1, 3). B = (-3, -5) C = (12, -1)
(x1, y1). (x2, y2) (x3, y3)
Therefore the area of triangle = 52 sq units
Hope you get your answer
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