Question

find the area of triangle whose vertices are (1,-6) (2,-4) and (-5,3)​

Answer 1

Area of a triangle with vertices (x

1

,y

1

) ; (x

2

,y

2

) and (x

3

,y

3

) is

∣

∣

∣

∣

∣

2

x

1

(y

2

−y

3

)+x

2

(y

3

−y

1

)+x

3

(y

1

−y

2

)

∣

∣

∣

∣

∣

Hence, substituting the points (x

1

,y

1

)=(1,2) ; (x

2

,y

2

)=(−3,4) and (x

3

,y

3

)=(−5,6) in the area formula, we get

Area of triangle =

∣

∣

∣

∣

∣

2

(1)(4−6)+(−3)(6−2)+(−5)(2−4)

∣

∣

∣

∣

∣

=

∣

∣

∣

∣

∣

2

−2−12+10

∣

∣

∣

∣

∣

=

2

4

=2 sq units

Answer 2

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