Math, asked by wwwsolution, 8 months ago

find the area of triangle whose vertices are (2,1),(3,-1),(0,3)​

Answers

Answered by radha2216
3

Answer:

-1

Step-by-step explanation:

A=½[x1(y2-y3) + x2(y3-y1) + x3(y1-y2)]

=½[2(-1-3) + 3(3-1) + 0(1-(-1))]

=½[ -8 +6 ]

= ½(-2)

= -1

Answered by srimothi04gmailcom
0

Step-by-step explanation:

Find the area of the triangle whose vertices are

(2, 3), (-1, 0), (2, -4)

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