find the area of triangle whose vertices are (2,1),(3,-1),(0,3)
Answers
Answered by
3
Answer:
-1
Step-by-step explanation:
A=½[x1(y2-y3) + x2(y3-y1) + x3(y1-y2)]
=½[2(-1-3) + 3(3-1) + 0(1-(-1))]
=½[ -8 +6 ]
= ½(-2)
= -1
Answered by
0
Step-by-step explanation:
Find the area of the triangle whose vertices are
(2, 3), (-1, 0), (2, -4)
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