find the area of triangle whose vertices are( 2, 2 )(4, 4 )and( 2, 6)
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Step-by-step explanation:
let us consider the triangle is triangle ABC, where the coordinates are ,
A (2,2) = (Ax,Ay)
B (4, 4 )= (Bx,By)
C( 2, 6) = (Cx,Cy)
we know the formula to find the area of triangle when the coordinates of vertices are given ,
Are of triangle = |Ax(By−Cy)+ Bx(Cy−A y)+ Cx(Ay−By)| / 2
Area of rectangle ABC
=|2(4 - 6)² +4(6 - 2)² +2(2 - 4)²|/2
=|2(-2)² + 4(4)² + 2 (-2)² |/2
=|2 x 4 + 4 x 16 + 2 x 4 | /2
=| 8 + 64 + 8 |/2
=| 16 + 64 |/2
=80/2
= 40 squnit
Area of given triangle is 40squnit.
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