Question

find the area of triangle whose vertices are( 2, 2 )(4, 4 )and( 2, 6)

Answer 1

Step-by-step explanation:

let us consider the triangle is triangle ABC, where the coordinates are ,

A (2,2) = (Ax,Ay)

B (4, 4 )= (Bx,By)

C( 2, 6) = (Cx,Cy)

we know the formula to find the area of triangle when the coordinates of vertices are given ,

Are of triangle = |Ax(By−Cy)+ Bx(Cy−A y)+ Cx(Ay−By)| / 2

Area of rectangle ABC

=|2(4 - 6)² +4(6 - 2)² +2(2 - 4)²|/2

=|2(-2)² + 4(4)² + 2 (-2)² |/2

=|2 x 4 + 4 x 16 + 2 x 4 | /2

=| 8 + 64 + 8 |/2

=| 16 + 64 |/2

=80/2

= 40 squnit

Area of given triangle is 40squnit.