Question

Find the area of triangle whose vertices are (2 , 3) (3,2) (4 ,5)​

Answer 1

$\huge\purple{Required \: Answer :}$

Area of Triangle -

$= \frac{1}{2} (x_{1}( y_{2} - y_{3} ) + x_{2}( y_{3} - y_{1}) + x_{3}( y_{1} - y_{2} ) ) \\ = \frac{1}{2} (2(2 - 5) + 3(5 - 3) + 4(3 - 2) \\ = \frac{1}{2} (2 \times - 3 + 3 \times 2 + 4 \times 1) \\ = \frac{1}{2} ( - 6 + 6 + 4) \\ = \frac{1}{2} (4) \\ = 2 \: {cm}^{2}$

Therefore, Area of Triangle is 2 ${cm}^{2}$