Question

Find the area of triangle whose vertices are (2 , 3) (3,2) (4 ,5)​

Answer 1

Answer:

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Answer 2

Answer:

2 unit sq.

Step-by-step explanation:

Area of a triangle =

$\frac{1}{2}|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|$

Now Let

$x_1 =2,y_1=3\\x_2 =3,y_2=2\\x_3 =4,y_3=5$

Therefore now putting values

$\frac{1}{2}|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|\\\frac{1}{2}|2(2-5)+3(5-3)+4(3-2)|\\\frac{1}{2}|2(-3)+3(2)+4(1)|\\\frac{1}{2}|-6+6+4|\\\frac{1}{2}|4| = \frac{1}{2}*4 = 2$

Therefore 2 unit sq.