Math, asked by pasharuwaid, 1 month ago

find the area of triangle whose vertices are (2 ,7 )(1 ,1 ) and
(10 ,8)​

Answers

Answered by arsh22mar2010
0

Answer:

The area of triangle is given by = 1/2|[-2 (1 – 8) -7 (1 – 10) + 1 (8 – 10)]| = 1/2|-14 + 63 – 2| = 47/2 sq.unitsRead more on Sarthaks.com - https://www.sarthaks.com/585622/find-the-area-of-the-triangle-with-vertices-2-7-1-1-and-10-8-using-determinant-method

Answered by prasunmishra
1

Answer:

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