Find the area of triangle whose vertices are
(-3.1).(1.–3) and (2.3).
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Answered by
1
Answer:
The area of the triangle formed by the given points is equal to
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0
Answer:
14sq.units
Step-by-step explanation:
(x1,y1)=(-3,1). (x2,y2)=(1,-3). (x3,y3)=(2,3)
Ar(∆) = 1/2[x1(y2-y3)+x2(y3-y1)+x3(y1-y2)]
=1/2[-3(-3-3)+1(3-1)+2(1-(-3))]
=1/2[18+2+8]
=1/2(28)
=14 sq.units
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