Question

find the area of triangle whose vertices are (3,1), (-1,3) and (-3,-2).

Answer 1

Formula For Finding Area of a Triangle by its vertices :

= $\frac{1}{2} | x_{1}  ( y_{2} - y_{3}   ) + x_{2} ( y_{3} - y_{1}) + x_{3} ( y_{1} - y_{2} )|$

Here vertices are (3,1), (-1,3) and (-3,-2)

x₁ = 3 , x₂ = -1 & x₃ = -3

y₁ = 1 , y₂ = 3 & y₃ = -2

Area = $\frac{1}{2} | 3 ( 3 - (-2) ) + (-1)(-2 - 1 ) + ( (-3) ( 1 - 3 ) |$

$= \frac{1}{2} | 15 + 3 + 6 |$

= 12 sq.units

Answer 2

Answer:

Step-by-step explanation: