Question

Find the area of triangle whose vertices are(-4,-2) (2,3) (3,-2)

Answer 1

Find the area of a triangle whose vertices are A (2, 4,2), B (3,-2,2), C (-2. Find the area of a triangle whose vertices are A (2,4,2), B (3,-2,2), C (-2,3,4).

Answer 2

Answer:(7+√87)sq units

Step-by-step explanation:

Let A(-4,-2), B(2,3) and C(3,-2) are the three vertices of a triangle ABC.

Now , AB=√(2+4)^2+(3+2)^2

=√36+25=√61 unit

Similarly, BC=√(3-2)^2+(-2-3)^2

=√1+25=√26 unit

And CA=√(3+4)^2+(-2+2)^2

√49+0=7 unit

Now area of triangle = sum of all sides

=(√61+√26+7 )sq units

=(7+√87) sq units