Question

find the area of triangle whose vertices are 4, 3, - 1, 0 and 2 - 4

Answer 1

Given :

A(2,3) B(-1,0) C(2,-4)

x1=2, x2=-1 ,x3=2,y1=3,y2=0,y3= -4

Area of triangle = 1/2  {x1(y2-y3) + x2(y3-y1) + x3(y1-y2)}

=1/2 {2(0-(-4)) + (-1) (-4-3) + 2(3-0)}

=1/2 {8-(-7)+6}

=1/2 {8+7+6}

=1/2 * 21

=21/2

Hope it helps!!

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