Question

Find the area of triangle whose vertices are (4,4) (3,-2) and (-3,16)

Answer 1

$\Large\frak{\underline{\underline{Answer:}}}$

ANSWER IS 32

Step-by-step explanation:

$x1 = 4 \: \: \: \: \: \: \: \: \: y1 = 4\\ x2 = 3 \: \: \: \: \: \: \: \: \: y2 = - 2\\ x3 = - 3 \: \: \: \: \: \: y3 = 16$

$from \: \: \: formula \\ triangle \: area \: \\ = \frac{1}{2} |x1(y2 - y3) + x2(y2 - y1) + x3(y1 - y2)| \\ \\ = \frac{1}{2} |4( - 2 - 16) + 3(16 - 4) + ( - 3)( 4 - ( - 2))| \\ \\ = \frac{1}{2} |4( - 18) + 3(12) - 3(6)| \\ \\ = \frac{1}{2} | - 72 + 26 - 18| \\ \\ = \frac{1}{2} | - 64| \\ \\ = \frac{1}{2} \times 64 \\ \\ = 1 \times 32 \\ area \: of \: triangle \: is \: = 32$

please Mark as brainly answer

Answer 2

Answer:

By using area of triangle method

Step-by-step explanation:

*Area of triangle = 1/2[ x1 ( y2- y3) + x2( y3-y1)+ x3(y1-y2)]

Here (x1,y1)= (4,4). ( x2,y2)=(3,-2) (x3,y3)=(-3,16)

Substitute all the values in the formula

area of ∆=1/2[ 4(-2-16)+3(16-4)+(-3)(4-(-2)]

=1/2[4(-18)+3(12)-3(4+2)]

=1/2[-72+36-18]

=1/2[- 90+36]

=1/2[-54]

= - 27