find the area of triangle whose vertices are (4, 6),(3, 4) and (6, 2).
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Solution:-
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Area of triangle :-1/2[x1(y2-y3)+x2(y3-y1)+x3(y1-y2)]
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According to figure
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=>1/2[4+(4-2)+3(2-6)+6(4-3)
=>1/2[4(2)+3(-4)+6(1)]
=>1/2[8-12+6]
=>1unit square area
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hope helps ✊
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