Question

Find the area of triangle whose vertices are (4,7) (1,13) (5,1)
10sq unit
11 sq unit
14 sq unit
16 sq unit​

Answer 1

Answer:

11sq units

Step-by-step explanation:

Let, A(4,7) B(1,3) C(5,1)

Here,

X1=4,Y1=7

X2=1,Y2=3

X3=5,Y3=1

Area of ∆=1/2[X1(Y2-Y3)+X2(Y3-Y1)+X3(Y1-Y2)]

=1/2[4(3-1)+1(1-7)+5(7-3)]

=1/2[4×2+1×-6+5×4]

= 1/2[8-6+20]

=1/2[8+14]

=1/2[22]

=11sq units

Your answer is 11sq units

Hope it helps you.

if yes then plz mark my answer the brainliest and if not then sorry

Answer 2

Hence, the required answer is 6 sq units