Question

Find the area of triangle whose vertices are (6,6),(2,3)and (4,.7)​

Answer 1

Answer:

1/2  x (-3) +1 + 3

0.5

Step-by-step explanation:

Answer 2

Concept:

Triangle is a 2D shape having three sides and three angles.

Given:

We have,

The vertices are (6,6), (2,3), and (4,7)​.

Find:

We are asked to find the area of a triangle.

Solution:

We have,

The vertices are (6,6), (2,3), and (4,7)​,

Here,

x₁ = 6, x₂ = 2, x₃ = 4

And,

y₁ = 6, y₂ = 3, y₃ = 7

So,

To find the area of a triangle we will you following formula,

Area of triangle = 1/2[x₁(y₂ - y₃) + x₂(y₃ - y₁) + x₃(y₁ - y₂)]

Now,

Putting values,

We get,

Area of triangle = 1/2[x₁(y₂ - y₃) + x₂(y₃ - y₁) + x₃(y₁ - y₂)]

i.e.

Area of triangle = 1/2[6(3 - 7) + 2(7 - 6) + 4(6 - 3)]

On solving we get,

Area of triangle = 1/2 × [-24 + 2 + 12]

We get,

Area of triangle = 1/2 × (-10)

i.e.

Area of triangle = -5

Hence, the area of a triangle with given vertices will be -5.

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