Question

find the area of triangle whose vertices are (7,0) , (0,0) and (0,-7)
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Answer 1

Answer:

The most general way to find the area of a triangle given three or more dimensional coordinates is to use Archimedes' Theorem. A triangle with squared sides A, B, and C has an area a that satisfies:

16a2=4AB−(C−A−B)2

Here we have

A=22+32=13

B=22+52=29

C=32+52=34

16a2=4(13)(29)−(34−13−29)2=1444

a=√144416=192

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