Question

Find the area of triangle whose vertices are (a) (2,3) (3,2) (5,0) ​

Answer 1

Step-by-step explanation:

Area of a triangle=1/2{x1(y2-y3)+x2(y3-y1)+x3(y1-y2)}

by this we can substitute the above values

(2,3),(3,2),(5,0)

=1/2{2(2-0)+3(0-3)+5(3-2)}

=1/2{4-9+5}

=0

Area of the triangle is 0