Question

find the area of triangle whose vertices are A(2,3) B(4,-4) C(2,6)
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Answer 1

Answer:

use the formula 1/2 {x1(y2-y3) +x2 (y3-y1) +x3(y1-y2)

solution. 1/2 2(-4-6) + 4(6-3)+2 (3-(-4)

1/2 2×-10 +4×3 + 2×7

1/2 -20 + 12+ 14

1/2 -20 +26

1/2 6

6/2= 3

answer was 3 hope its help you .

Answer 2

Answer:

3 sq.units

Step-by-step explanation:

We know,Area of the triangle is equal to 1/2 x1(y2-y3)+x2(y3-y1)+x3(y1-y2).

Here,X1=2

X2=4

X3=2

And

Y1=3

Y2=-4

Y3=6

Area=1/2[ 2(-4-6)+4(6-3)+2(3-(-4))]

= 1/2[2(-10)+4(3)+2(7)]

=1/2[-20+12+14]

=1/2(6) sq.units.

= 3 sq.units.