Question

find the area of triangle whose vertices are A(-3,2)B(4,5)C(6,2)​

Answer 1

Answer:

27/2 sq,units

Step-by-step explanation:

Given,

A = (-3 , 2)

B = (4 , 5)

C = (6 , 2)

To Find :-

Area of the triangle.

Formula of Area of triangle :-

$Area = \dfrac{1}{2}|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|$

Solution :-

• x_1 = -3 , y_1= 2
• x_2 = 4,y_2 = 5
• x_3 = 6 , y_3 = 2

$Area = \dfrac{1}{2}|-3(5-2)+4(2-2)+6(2-5)|$

$=\dfrac{1}{2}|-3(3)+4(0)+6(-3)|$

$=\dfrac{1}{2}|-9+0-18|$

$=\dfrac{1}{2}|-27|$

$=\dfrac{27}{2}sq.units$