Find the area of triangle whose vertices are A. (4,3) B. (6,8) C. (2,6)
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Answer:
x1=4,y1=3
x2=6 ,y2=8
x3=2, y3=6
area of=1/2[x1(y2-y3) + x2(y3-y1) + x3(y1-y2)]
=1/2[4*(8-6)+6*(6-3)+2*(3-8)]
=1/2[4*2+6*3+2*(-5)]
=1/2[8+18-10]
=1/2[26-10]
=1/2[16]
=8
answer is 8
hope it will help u!!!!
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