Question

Find the area of triangle whose vertices are A(5,0)and B(8,0 )and C(8,4)
in a square units

Answer 1

Step-by-step explanation:

x1=5 x2=8 x3=8

y1=0 y2=o y3=4

area of triangle=1/2[x1(y2-y3) +x2(y3-y1)+x3(y1-y2)]

=1/2[5(0-4)+8(4-0)+8(0-0)]

=1/2[5×(-4)+8(4)+8(0)]

=1/2[-20+32+0]

=1/2×12

=6square units

Answer 2

Answer:

6 sq units

Step-by-step explanation:

The area of a triangle with vertices A(5, 0), B(8, 0) and C(8, 4) in square units is.

=12|-20+32|

=(12×12)

=6 sq units