Question

Find the area of Triangle whose vertices are (a,bc),(b,ca),(c,ab)

Answer 1

Step-by-step explanation:

1/2a²b²c²..............

Answer 2

angle of triangleb(A)

$|x1(y2 + y3) + x2(y3 - y1) + x3(y1 + y2) \div 2 \\ |$

hence,substituting the points

$(x1y1) = (ab + c)(x2 + y2) - (ab - c)and(x3y3) = ( - ac)$

$a = |a(b - c - c) + a(c - b - c) - a(b + c - b +c) \div 2|$

$|a(b - 2c) + a( - b) - a(2c) \div 2|$

$|ab - 2ac - ab - 2ac \div 2|$

$| - 4ac \div 2|$

$= 2ac$