Question

find the area of triangle whose vertices are given as (1 -1) (-4 6) and (-3 -5)​

Answer 1

well you may solve this question by

Answer 2

Answer:

Step-by-step explanation:

Area of∆= 1/2{(X1(y2-y3)+X2(y3-y1)+x3(y1-y2)}

Area of ∆ =1/2{1(6+5)-4(-5+1)-3(-1-6)}

=1/2{11+16+21}

=1/2×48= 24 sq units

Plzzz mark brainleist