find the area of triangle whose vertices are p(3/2 ,1) q(4, 2) r(4, -1/2).
ans should be 25/8 sq unit
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First find its coordinates by
x1 + x2 ÷2......
Then find sub perimeter by
s=( a+b+c)÷2
Then put the values in herons formula...
area of tri = {s(s-a)(s-b)(s-c)}
You will get your answer....
It's too difficult to type otherwise I would have solve it.....
HOPE IT WOULD HELP YOU KID.....
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