find the area of triangle whose vertices are P=(-5,7) ,R=(-1,6),S=(4,5)
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2
Answer:
Given data :-
P(−5,7)≡(x
1
,y
1
)
Q(−4,−5)≡(x
2
,y
2
)
R(4,5)≡(x
3
,y
3
)
To find :- Area of triangle PQR
Solution :-
Ref. image
P(x
1
,y
1
),Q(x
2
,y
2
),R(x
3
,y
3
) are vertices of a triangle
ar(△PQR)=
2
1
[x
1
(y
2
−y
3
)+x
2
(y
3
−y
1
)+x
3
(y
1
−y
2
)]
=
2
1
[−5(−5−5)−4(5−7)+4(7+5)]
=
2
1
[50+8+48]
=
2
1
[50+56]
=
2
1
×106
=53sq.unit
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