Question

Find the area of triangle whose vertices as x (4,-3) Y(-6,-3) and z (0,-3) justify your answer

Answer 1

if $(x_1,y_1),(x_2,y_2)$ and $(x_3,y_3)$ are given
then, area of triangle is given by,
$\triangle=\frac{1}{2}[x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)]$

here, given vertices of triangle are ; x(4, -3) , y(-6,-3) and z(0, -3)

so, area of triangle = 1/2 [4(-3 + 3) + (-6)(-3 + 3) + 0(-3 + 3) ] = 0

justifying : actually, area of triangle will be zero only when all the three points lies in a line. I mean, points are colinear then area of triangle will be zero .

here, if you locate the point in Cartesian coordinate system you will observe that points lie in a line. [ see figure . ] hence area of triangle is zero.

Answer 2

Answer:

Justification is that the points are

Colinear they all lei in a same line therefore area is zero