Find the area of triangle whoses vertices are:(1,6) (3,0) (-3,-7).
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1, 6. 3 , 0. -3 , -7
-1.-6. -1.-3. -1. -3
0. 0. 2. -3. -4. -10
1/2(2. -3
-4. -10)
1/2(-20-(-3)(-4))
1/2 (-20-12)
1/2(-32)
=-16
as area can't be negative so we accept it as positive so the answer is 16 Square units
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