find the area of triangle with sides 12 CM 10 cm 14 cm
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answer:
Let a = 10 cm., b = 12 cm., c = 14 cm.
Area ir the triangle =
√
s(s−a)(s−b)(s−c)
s=
a+b+c
2
=
10+12+14
2
=
36
2
=18
Area of the triangle =
√
18(18−10)(18−12)(18−14)
=
√
18×8×6×4
=
√
9×2×8×6×4
==3×4×26–√=246–√ sq.cm.
Benak:
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