Question

Find the area of triangle with two sides of which are 16cmand 22cm and perimeter 64cm

Answer 1

Here, a= 16cm, b= 22cm, let c = 'x' cm
Perimeter= a+b+c= 64= 16+22+c= c=26cm= s= a+b+c/2 =64/2 = 32cm
Area= (sq root)s(s-a)(s-b)(s-c)= (sq root) 32(32-16)(32-22)(32-26)= (sq root) 32x16x10x6= 32 root30 =
Ans: 175.2 sq.cm

Answer 2

Answer:

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Step-by-step explanation: