Question

Find the area of triangle with vertices, P(2, 7), Q(5, 3) and R(-2, -3).​

Answer 1

Answer:

Area of a triangle is determinant

1/2|x1 y1 1 x2. y2 1 x3 y3 1|

Answer 2

Answer:

0

Step-by-step explanation:

(x1,y1)=(2,7)

(x2,y2)=(5,3)

(x3,y3)=(-2,-3)

Area of a triangle =1/2{[(x1*y2)+(x2*y3)+(x3*y1)]-[(x2*y1)+(x3*y2)+(x1*y3)]} sq. units

                             =1/2{[(2*3)+(5*-3)+(-2*7)]-[(5*7)+(-2*3)+(3*-2)]}

                              =1/2{[(-23)]-[(-23)]}

                               =1/2*0

                               =0

since the area is zero the points are collinear