Question

Find the area of triangle with verticle(1,1),(2,3) and (4,5) and i will fallow them​

Answer 1

Answer:

1 units²

Explanation:

Let the triangle be ABC, with vertices,

• A(1, 1)
• B(2, 3)
• C(4, 5)

Area of the triangle :

$\rm \longrightarrow \dfrac{1}{2}|x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_1(y_1 - y_2) |$

Where,

• $\rm x_1 \: \& \: y_1 = 1, \: 1$
• $\rm x_2 \: \& \: y_2 = 2, \: 3$
• $\rm x_3 \: \& \: y_3 = 4, \: 5$

On substituting the values,

$\rm \longrightarrow \dfrac{1}{2}|1(3 - 5) + 2(5 - 1) + 4(1 - 3) |$

$\rm \longrightarrow \dfrac{1}{2}|1( - 2) + 2(4) + 4( - 2) |$

$\rm \longrightarrow \dfrac{1}{2}|- 2 + 8 - 8 |$

$\rm \longrightarrow \dfrac{1}{2}|-2|$

$\rm \longrightarrow \dfrac{1}{2} \times 2$

$\rm \longrightarrow 1 units^2$

∴ Area of the triangle = 1 units²