find the area of triangle XYZ and the length of AY . answer is 24cm sq. and 4.8 cm . I want solution
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Step-by-step explanation:
ArEa XYZ=1/2 x XY x YZ = (8x6)/2=24sq.cm. 1
areA xyz = 1/2 x XZ x AY (1/2bh)
XZ= √8x8+6x6=√100= 10cm
1/2bh=24sq.cm. (from 1)
h =(24 x2)/b=48/10=4.8cm
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