Question

find the area of triangles ABC in which angle B=60degree ,angle C =90degree, AB=20cm and AC =5cm​

Answer 1

Answer:

ab=20

ac = 5

angle b= 60

so tan 60 =

$1 \div \sqrt{3} = 5 \div bc$

so

$bc = 5 \div \sqrt{3}$

area

$1 \div 2 \times 5 \times 5 \times 1.732 = 21.65$