find the area of triangles two sides of which are 13 cm and 10 cm de permeter is 42 cm
Answers
Answered by
1
Answer:
4 root 231
Step-by-step explanation:
perimeter = 42cm
two sides are given 10 and 13cm
third side = 42-13+10 = 42-23 = 19cm
s = perimeter/2 = 42/2 = 21cm
area of triangle = s(s-a)(s-b)(s-c)
= 21(21-10)(21-13)(21-19)
= 7 * 3 * 11 * 8 * 2
= 4root 231
mark it brainiest!!
Similar questions