Question

find the area of trianglewhose sidesare 13 ,14,and 15

Answer 1

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Answer 2

$given \: three \: sides \: a = 13 \: b = 14 \: c = 15 \\ then \: s = \frac{1}{2}(a + b + c) = 21 \\ also \: (s - a) = 8 \: (s - b) = 7 \: (s - c) = 6 \\ so \: area \: = \sqrt{s(s - a)(s - b)(s - c)} = \sqrt{21 \times 8 \times 7 \times 6 } = 84$