Question

find the area of triangular field whose sides are 78m,50m,112m .

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Answer 1

Answer:

Step-by-step explanation:

Given as :

The side of triangle are

Let AB = a = 78 m

    BC = b = 50 m

    CA = c = 112 m

Applying Heron's formula

S =  a+b+c/2,

Or, S =78+50+112/2,

Or,S=240/2=120.

Area of triangle = √s(s-a)(s-b)(s-c),

Area of triangle =√120(120-78)(120-50)(120-112),

Area of triangle =√120*42*70*8,

Area of triangle =√2822400,

∴   Area of triangle = 1680   m² ,

Hence, The  Area of triangle is 1680 m²,Answer.

Hope it helps you.

Answer 2

Answer:

A=1680m²

A=1680m²a Side 78m

A=1680m²a Side 78mb Base 50m

A=1680m²a Side 78mb Base 50mc Side 112m

Using the formulas

A=(root)s(s﹣a)(s﹣b)(s﹣c)

s=a+b+c

2

Solving forA

A=1/4(root)﹣a4+2(ab)2+2(ac)2﹣b4+2(bc)2﹣c4

=1/4·﹣784+2·(78·50)2+2·(78·112)2﹣504+2·(50·112)2﹣1124=1680m²