Question

Find the area of triangular field whose sides measure 156m,169m, and 65 m determine the length of its shortest altitude

Answer 1

Answer:

Step 1: Find the perimeter:

1980 / 18 = 110

Step 2: Find the length:

110 - 23 * 2 = 64 / 2 = 32tep-by-step explanation:

Answer 2

Answer:

Area=5070m²

Shortest altitude=60m

Step-by-step explanation:

let the sides be a,b&c

Semiperimeter (s)

= (65+156+169)/2

= 390/2

= 195

area = √s(s-a)(s-b)(s-c)

= √195(195-65)(195-156)(195-169)

= √ 195(130)(39)(26)

= √ 25704900

= 5070m²

area of ∆ = 1/2 × base × height

Or,5070 = 1/2 × 169(largest base)× altitude

Shortest altitude = 5070÷169/2

= 60m

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