Question

Find the area of triangular park whose sides are of length 120m,80m,50m.

Answer 1

Answer: 1125√3

Step-by-step explanation:

S=a+b+c/2

S=120+80+50/2

S=250/2

S=125m

area of triangle= √S (s-a)(s-b)(s-c)

=√125(125-120)(125-80)(125-50)

=√125(5)(45)(75)

=√5×5×5×5×5×3×3×3×3×5×3

let the no. be common

=5×5×5×3×3√3

=1125√3

Answer 2

Answer:

Step-by-step explanation:

a=120m

b=80m

c=50m

S=a+b+c/2

=120+80+50/2

=250/2

=125

Therefore,area=√s(s-a)(s-b)(s-c)

=125(125-120)(125-80)(125-50)

=125(5)(45)(75)

=√125×5×45×75

=25×5×5+×9×5×25×5