Find the area of whose sides are 60 cm, 153 cm and 111 cm.
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As you didn't mentioned the shape..
so I hope it's a tri angle
and then as per the formula the area will be
√s(s-a)(s-b)(s-c) where s is the half of its parameter.
so
the parameter of this triangle is-(60+111+153)cm
= 324cm
and half of the parameter is- 324/2cm= 162cm
now the area will be-
√162 (162-60)(162-111)(162-153)cm²
=√162×102×51×9cm²
=√3×17×3×3×3×2×1×2×1cm²
=3×3×2√17cm²
= 18√17cm2
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