Find the area of x .if the area of the triangle formed by (-2,2),(-1,-3) ,(x,0)is 3sq.units
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area of ∆ =
1/2{ x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2) }
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we are given three vertices of a triangle,
- A(-2,2)
- B(-1,-3)
- C(x,0)
and it's area,
- 3 sq. units
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substituting values in the formula,
area =
1/2 {-2(-3-0) + (-1)(0-2) + x(2-(-3) } = 3
1/2 { -2(-3-0) -1(2) + x(2+3) }= 3
1/2 { 6 - 2 + 2x + 3x } = 3
{ 4 + 5x } = 3 x 2
4 + 5x = 6
5x = 6 - 4
5x = 2
x = 2/5
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