Question

find the area or the triangle whose vertices are (4,7)(1,3) (5,1)

Answer 1

Let A(4,7), B(1,3), C(5,1)

Here , x1= 4, y1=7

x2=1, y2=3

x3=5, y3=1

Area of ∆ = 1/2 [(x1(y2-y3) +x2(y3-y1)+ x3(y1-y2)

Area of ∆ = 1/2[ 4(3-1)+1(1-7)+5(7-3)

= 1/2[ 4×2+1×-6+5×4]

= 1/2[8-6+20]

=1/2[ 2+20]

=1/2[22]

= 22/2

= 11

Hence, area of ∆ = 11 sq.units

hope this will help you :)

Answer 2

answer is given above.