find the area othe tiangle, two sides of which are 15 cm and 28 cm and the perimeter is 84 cm .
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Answered by
2
Answer:
Step-by-step explanation:
Perimeter of the triangle =a+b+c
84=15+28+c
84-43=c
41=c
Area of triangle=A=s(s﹣a)(s﹣b)(s﹣c)
s=a+b+c/2
Solving forA
A=1
4﹣a4+2(ab)2+2(ac)2﹣b4+2(bc)2﹣c4=1
4·﹣154+2·(15·28)2+2·(15·41)2﹣284+2·(28·41)2﹣414=126
Answered by
4
Step-by-step explanation:
Perimeter = A + B + C
84 = 15+28+ C
84 = 43 + C
C = 84-43
C = 41 cm
As we have the length of all the sides but we dont know the base and height....so we cant use the formulae of Area = 1/2× b × h
So here we need to use herons formulae
U can check the attachment
Plz mark it as brainlist....if it helps u
Thank u :)
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