Question

find the area swepeed by minuit hand of length14cm in 35min of clock​

Answer 1

the answer:-

The area swept by min hand clock of length 14cm in 35min

=are of sector with angle 210

=

$(210 \div 360) \times \pi \times 14 ^{2}$

=

$(7 \div 12) \times (22 \div 7) \times 19$

=

$359.3$

the final answer is 359.3cm^2