find the area to the nearest square meter of the canvas required to make a right circular conical tent 30m in perpendicular height and covering 1386m square of ground
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2πr = 1386
r = 220.5
canvas required = πr(l+r)
= 22/7×220.5(1120.5+220.5)
= 22/7×220.5×1341
= 22×31.5×1341
= 929313 m² ans.
r = 220.5
canvas required = πr(l+r)
= 22/7×220.5(1120.5+220.5)
= 22/7×220.5×1341
= 22×31.5×1341
= 929313 m² ans.
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1
Answer:
Step-by-step explanation:
2417m² ans
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