Question

find the area unclosed by y^2 = 8x and the line x = 2​

Answer 1

Answer:

Step-by-step explanation:

1+x  

2

 

1

​

−log(1+x  

2

)

y  

2

=8x

y=  

8x

​

 

y=2  

2x

​

 

area=2  

0

∫

2

​

ydx=2  

0

∫

2

​

2  

2

​

 

x

​

dx

=4  

2

​

 

0

∫

2

​

 

x

​

dx=4  

2

​

[  

3/2

x  

3/2

 

​

]  

0

2

​

 

=  

3

8  

2

​

 

​

[2  

3/2

−0]=  

3

8  

2

​

 

​

2  

2

​

=  

3

32

​

 

​

 

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Answer 2

Answer:

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