Question

Find the area under the cure y=e^-x on interval[0,2]​

Answer 1

Answer:

The way this works is that you are going integrate y = e^x from 0 to 1 with respect to x.

The integral of e^x is e^x.

1 is the upper limit and 0 is the lower limit.

Applying the fundamental Theorem of Calculus, you get

e^1 - e^0 = e-1.

Answer: e-1.

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