Question

Find the area under the velocity- time graph.​

Answer 1

Answer:

Area of the figure is

Rectangle=ABCD

Area of rectangle= lxb

=18x10=180sq.unit

Area of triangleADE=½xbxh

=½x10x(36-18)

=10x9=90sq.unit

Total area= 180+90= 270sq.unit

Answer 2

Answer:

270

Explanation:

Let us take the quadrilateral AECB.

$AB=18\\EC=36\\BC=10\\area=\frac{1}{2} (AB+CE)BC\\area=27*10=270$