Question

find the areaof a rectangle whose length and breadth are 3x+2yand 4x-3y​

Answer 1

Answer:

Given -

Length = 3x+2y

Breadth = 4x-3y

To Find -

Area of rectangle

Formula used -

Area of rectangle = L× B

Solution -

$3x + 2y(4x - 3y)$

$= 3x(4x - 3y) + 2y(4x - 3y)$

$= {12x}^{2} - 9xy + 8yx - {6y}^{2}$

$= {12x}^{2} - xy - {6y}^{2}$

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Answer 2

Given -

Length = 3x+2y

Breadth = 4x-3y

To Find -

Area of rectangle

Formula used -

Area of rectangle = L× B

Solution -

3x + 2y(4x - 3y)3x+2y(4x−3y)

= 3x(4x - 3y) + 2y(4x - 3y)=3x(4x−3y)+2y(4x−3y)

= {12x}^{2} - 9xy + 8yx - {6y}^{2}=12x

2

−9xy+8yx−6y

2

= {12x}^{2} - xy - {6y}^{2}=12x

2

−xy−6y

2

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