Question

find the areas of a triangle whose base and attitude are 6cm and 3 cm respectively​

Answer 1

Answer:

$\mathtt \purple{ \mathtt{\boxed{Find \: the \: value : \sin ( \frac { \pi } { 2 } - \cos ^ { - 1 } \frac { 3 } { 7 } ) + \cos ( \frac { 3 \pi } { 2 } - \sin ^ { - 1 } \frac { 2 } { 7 } ) + \cos ( \tan ^ { - 1 } \frac { 7 } { 6 } )}}}$

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Answer 2

Given,

Length of base of the given triangle = 6cm

Length of altitude of the given triangle = 3cm

To find,

The area of the given triangle.

Solution,

We can simply solve this mathematical problem by using the following mathematical process.

Now,

Area of a triangle = ½ × base × altitude

So, by putting the given values, we get :

Area of the triangle = (½ × 6 × 3) cm²

Area of the triangle = (3×3) cm²

Area of the triangle = 9 cm²

(The initial length measurements were in cm unit and that's why we have used cm² unit for area measurement.)

Hence, the area of the triangle is 9cm²