Question

find the areas of shaded portion​

Answer 1

Answer:

area of triangle =1/2* base *height

=1/2*3*4=6

area of rectangle= l*b

=3*4=12

diagonal divides it into 2 equal parts so area of shaded part of rectangle is 12/2=6

area of shaded part = area of triangle +shaded area of rectangle

=6+12=18

hope it helps

plz mark my answer as brainliest

Answer 2

Answer:

Given:-

• Altitude of the triangles are 3 cm.

(Why? Because, it is noted in the diagram but in the second triangle, it makes a half of 6 cm i.e. 3 cm.

• Bases of the triangles are 4 cm.

To Find:-

Area of the shaded portion.

How can we find?

• At first, we have to find the area of the triangles.
• As they are congruent to each other, there is no need to find the second one.
• Let, the area of the first triangle and second triangles are q cm² and p cm² respectively.
• Then, we have to add the areas (p+q) cm².

PROCESS:-

Height/Altitude given = 3 cm

Base of the triangle = 4 cm

We know,

$\boxed{Area \ of \ triangle \ = 1/2 \times Perpendicular \ Height \times Base}$

Hence,

Area = 1/2 × 4 × 3 cm²

= 2 × 3 cm² {Cancelled 1/2 and 4 and result is 2}

= 6 cm²

Now, as per our plan,

They are congruent, i.e. area are same.

Hence,

2(6) cm²

= 12 cm²

REQUIRED ANSWER:-

Therefore, area of the shaded portion of the polygon is 12 cm².